Question

Найти величину каждого из двух одинаковых зарядов, если на расстоянии 6 см друг от друга они взаимодействуют с силой 0,4 мН. Определить напряженность поля на середине отрезка, соединяющего заряды.

Answer 1

так как заряды одинаковы, следовательно закон кулона: F=k*q^2/r^2. q выразить и посчитать. напряжённость: E=k*q/(r/2)^2

Answer 2

Calculation of the Magnitude of the Charges

To find the magnitude of each of the two identical charges, we can use Coulomb's law, which states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

Given: - Distance between the charges (d) = 6 cm = 0.06 m - Force between the charges (F) = 0.4 mN = 0.4 * 10^(-3) N

Using Coulomb's law, we can write the equation as:

F = (k * q1 * q2) / d^2

Where: - F is the force between the charges - k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2) - q1 and q2 are the magnitudes of the charges - d is the distance between the charges

Rearranging the equation to solve for q1 and q2:

q1 * q2 = (F * d^2) / k

Substituting the given values:

q1 * q2 = (0.4 * 10^(-3) * (0.06)^2) / (9 * 10^9)

Calculating the product of the charges:

q1 * q2 = 0.000144 / 9

q1 * q2 = 0.000016

Since the two charges are identical, we can assume q1 = q2 = q.

Therefore, q^2 = 0.000016

Taking the square root of both sides:

q = sqrt(0.000016)

Calculating the magnitude of each charge:

q ≈ 0.004

Therefore, the magnitude of each of the two identical charges is approximately 0.004 C.

Calculation of the Electric Field Intensity at the Midpoint

To determine the electric field intensity at the midpoint of the segment connecting the charges, we can use the formula:

E = (k * q) / r^2

Where: - E is the electric field intensity - k is the electrostatic constant (k = 9 * 10^9 Nm^2/C^2) - q is the magnitude of the charge - r is the distance from the charge

Since the charges are identical, we can assume q1 = q2 = q.

Given: - Distance between the charges (d) = 6 cm = 0.06 m

To find the electric field intensity at the midpoint, we need to find the distance from the midpoint to one of the charges. This distance is half the distance between the charges:

r = d/2 = 0.06/2 = 0.03 m

Substituting the values into the formula:

E = (9 * 10^9 * 0.004) / (0.03)^2

Calculating the electric field intensity:

E ≈ 1.6 * 10^6 N/C

Therefore, the electric field intensity at the midpoint of the segment connecting the charges is approximately 1.6 * 10^6 N/C.