Question

Радиолокатор гаи засек координаты машиных1=60 м у1=100 м. через 2 секунды координаты машины изменились:х2=100 у2=80 м. превысил ли водитель допустимую скорость 60 км/ч?

Answer 1

Скорость машины $\frac{\sqrt{(60-100)^2+(100-80)^2}}{2} =22.36$ м/c, а это больше 60 км/ч

Answer 2

Calculating Speed Exceeded by the Driver

To determine if the driver exceeded the permissible speed of 60 km/h, we can calculate the average speed of the vehicle between the two sets of coordinates provided.

Given: - Initial coordinates: (x1=60 m, y1=100 m) - Coordinates after 2 seconds: (x2=100 m, y2=80 m)

First, let's calculate the distance traveled by the vehicle using the coordinates provided.

The distance formula between two points (x1, y1) and (x2, y2) in a two-dimensional plane is given by: distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Using the given coordinates: distance = sqrt((100 - 60)^2 + (80 - 100)^2) distance ≈ sqrt(1600 + 400) ≈ sqrt(2000) ≈ 44.72 m

The distance traveled by the vehicle in 2 seconds is approximately 44.72 meters.

Now, let's calculate the average speed of the vehicle.

The average speed can be calculated using the formula: average speed = distance / time

Given that the time interval is 2 seconds, we need to convert this to hours for the speed calculation.

2 seconds = 2/3600 hours ≈ 0.00056 hours

Now, we can calculate the average speed: average speed = 44.72 m / 0.00056 hours ≈ 80000 m/h ≈ 80 km/h

The average speed of the vehicle between the two sets of coordinates is approximately 80 km/h, which exceeds the permissible speed of 60 km/h. Therefore, the driver has exceeded the permissible speed limit.