Question

В топке теплового двигателя при сжигании топлива за цикл выделилось количество теплоты равное 50 кДж КПД двигателя 20 Какую работу совершил тепловой двигатель за цикл.

Answer 1

Кпд=A/Q
A=кпд*Q=0,2*50=10 кДж

Answer 2

Calculation of Work Done by the Heat Engine

To calculate the work done by a heat engine, we need to know the amount of heat released during the cycle and the efficiency of the engine.

Given: - Amount of heat released during the cycle: 50 kJ - Efficiency of the engine: 20%

To calculate the work done by the heat engine, we can use the formula:

Work = Heat input - Heat output

Since the efficiency of the engine is given, we can calculate the heat input using the formula:

Efficiency = (Work / Heat input) * 100

Solving for heat input:

Heat input = (Work / Efficiency) * 100

Substituting the given values:

Heat input = (50 kJ / 20%) * 100

Calculating the heat input:

Heat input = 250 kJ

Now, we can calculate the work done by the heat engine:

Work = Heat input - Heat output

Substituting the values:

Work = 250 kJ - 50 kJ

Calculating the work done:

Work = 200 kJ

Therefore, the heat engine has done 200 kJ of work during the cycle.