Question

Капля, имеющая положительный заряд (-2е) при освещении потеряла один электрон. Каким стал заряд капли?

Answer 1

Потеря электрона означает увеличение заряда на e. Так что заряд станет -2+1 = -1e

Answer 2

Answer:

When a droplet with a positive charge of (-2e) loses one electron due to illumination, its charge becomes -e.

Explanation:

The initial charge of the droplet is -2e. When it loses one electron, the charge decreases by the charge of one electron, which is -e.

The charge of an electron is approximately -1.6 x 10^-19 coulombs.

Therefore, the new charge of the droplet after losing one electron is -e.