Question

Баллон, содержащий газ под давлением 2,8 МПа, находился на складе при температуре 280К. Когда баллон перенесли в другое помещение, давление газа в нем стало равным 3 МПа. Чему равна температура воздуха в этом помещении?

Answer 1

Уравнение Клапейрона при изохорном процессе(V=const)

P1=2,8*10^6

 

P2=3*10^6

T1=280К

T2=?

P1/T1=P2/T2=>T2=T1*P2/P1

T2=280*3*10^6/2,8*10^6=300К

Ответ:300К

 

 

 

 

 

 

 

 

 

 

Answer 2

Calculation of the Temperature in the New Room

To calculate the temperature in the new room, we can use the ideal gas law equation, which states that the pressure of a gas is directly proportional to its temperature when the volume and the amount of gas remain constant.

The ideal gas law equation is given by:

PV = nRT

Where: - P is the pressure of the gas - V is the volume of the gas - n is the number of moles of the gas - R is the ideal gas constant - T is the temperature of the gas

In this case, the volume and the amount of gas remain constant. Therefore, we can rewrite the equation as:

P1/T1 = P2/T2

Where: - P1 is the initial pressure of the gas - T1 is the initial temperature of the gas - P2 is the final pressure of the gas - T2 is the final temperature of the gas

Given that the initial pressure (P1) is 2.8 MPa, the initial temperature (T1) is 280 K, and the final pressure (P2) is 3 MPa, we can rearrange the equation to solve for the final temperature (T2):

T2 = (P2 * T1) / P1

Substituting the given values:

T2 = (3 MPa * 280 K) / 2.8 MPa

Now, let's calculate the value of T2:

T2 = (3 * 280) / 2.8 = 300 K

Therefore, the temperature in the new room is 300 K.