Question

.брусок лежит на наклонной доске. Как зависит сила трения покоя, действующая на брусок, от угла между доской и полом?

Answer 1

Ак как тело покоится то

Fтр=m*g*sina
если a=0 Fтр=0
если a увеличивается то Fтр пок увеличивается
при tga=k- брусок скользит и уже действует сила трения скольжения
Fтрск=k*m*g*cоsa

Answer 2

Frictional Force on an Inclined Plane

When a block is placed on an inclined plane, the force of friction acting on the block depends on the angle between the plane and the floor. The relationship between the force of friction and the angle can be explained as follows:

Static Friction: - The force of static friction, denoted as F, is the force that opposes the initial motion of an object at rest. - The maximum force of static friction can be calculated using the formula: F = μN, where μ is the coefficient of static friction and N is the normal force acting on the object. - The normal force N can be calculated using the formula: N = mg, where m is the mass of the object and g is the acceleration due to gravity.

Effect of Angle on Friction: - As the angle of the inclined plane increases, the component of the weight of the block acting parallel to the plane also increases. - This increase in the component of the weight parallel to the plane results in an increase in the force of friction acting on the block. - The relationship between the force of friction and the angle of the inclined plane can be expressed using the formula: F = μN = μmg. - The value of μ remains constant, but as the angle increases, the value of N and consequently F also increase.

Conclusion: - In summary, the force of friction acting on a block on an inclined plane increases as the angle between the plane and the floor increases. This is due to the increase in the component of the weight of the block acting parallel to the plane, which in turn increases the normal force and the force of friction.

I hope this explanation helps! If you have further questions or need additional information, feel free to ask.