Question

Средняя скорость поезда на всем пути 15м/с.С какой скоростью он двигался первые 6 с, если за остальные 12 с прошёл расстояние 150 м?

Answer 1

Vср=V1t1 + V2t2/t1+t2
V1t1+V2t2=Vср(t1+t2)
V1t1+V2t2=15м/с * 18 с =270 м    S=270
t2=12 с 
S2=150 м
V2=S2/t2=150/12=12.5 м/c
S=S1+S2
S1=S-S2= 270-150=120
t1=6 с
S1=120 м
V1=S1/t1=20 м/c 
Ответ в первые 6 секунд он двигался со скоростью 20м/c

Answer 2

Дано :                                    Решение :
V = 15 м / с .                          Формула средней скорости :
t1 = 6 c .                                 Считаем :
t2 = 12 c .                               S1 = 15 * ( 6 + 12 ) -150 = 120 м .
S2 = 150 м .                            Скорость есть отношение пути ко времени в пути :
V1 - ?                                      Считаем :
                                               V1 = 120 / 6 = 20 м / с .
                                               Ответ : V1 = 20 м / с .                       

Answer 3

Calculation of the Train's Speed

To calculate the speed at which the train was moving during the first 6 seconds, we can use the formula:

Speed = Distance / Time

Given that the train traveled a distance of 150 meters in the remaining 12 seconds, we can substitute these values into the formula:

Speed = 150 meters / 12 seconds

Calculating this, we find that the speed of the train for the remaining 12 seconds is 12.5 meters per second.

Now, to find the speed of the train during the first 6 seconds, we can use the fact that the average speed of the train for the entire journey is 15 meters per second. We can assume that the speed of the train during the first 6 seconds is the same as the average speed.

Therefore, the speed of the train during the first 6 seconds is 15 meters per second.

Please note that the search results did not provide a direct answer to this specific question. However, the calculation is based on the formula for speed and the given information about the distance and time traveled by the train.