Question

Воду погрузили тело объемом 120 кубических см определите значение выталкивающей силы действующей на тело

Answer 1

Дано V=120*10^-6 м3=1,2*10^-4 м3

Fa=p*g*V=1000*10*1,2*10^-4=1,2 Н

Ответ Fa=1,2 Н

Answer 2

Ρ - плотность воды ( 1000 кг / м³ )
V - объем тела ( 120 см³ = 0.00012 м³
g - ускорение свободного падения ( 10 Н / кг )
F - сила Архимеда ( выталкивающая ) - ?

F = ρ * g * V = 1000 кг / м³ * 10 Н / кг * 0.00012 м³ = 1.2 Н

Ответ : 1.2 Н

Answer 3

Calculation of the Buoyant Force

To determine the value of the buoyant force acting on the body submerged in water, we can use the formula:

F = ρ * V * g

Where: - F is the buoyant force - ρ is the density of the fluid (in this case, water) - V is the volume of the body submerged in the fluid - g is the acceleration due to gravity

In this case, the volume of the body is given as 120 cubic centimeters (cm³).

Density of Water

The density of water is approximately 1 gram per cubic centimeter (g/cm³) or 1000 kilograms per cubic meter (kg/m³).

Acceleration Due to Gravity

The acceleration due to gravity is approximately 9.8 meters per second squared (m/s²).

Calculation

Using the given volume of 120 cm³ and the density of water, we can calculate the buoyant force as follows:

F = ρ * V * g

F = (1 g/cm³) * (120 cm³) * (9.8 m/s²)

Converting the units to be consistent:

F = (1 kg/m³) * (0.00012 m³) * (9.8 m/s²)

F ≈ 0.001176 N

Therefore, the value of the buoyant force acting on the body submerged in water is approximately 0.001176 Newtons (N).

Please note that the above calculation assumes that the body is fully submerged in water and that the water is at a standard temperature and pressure.

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