Question

Определите силу тока в проводнике, находящегося в однородном магнитном поле с индукцией 2мТл, если длина проводника 20см, а сила Ампера действующая на проводник 0,75 мкН. Угол между магнитной индукцией и током 90°.

Answer 1

Fa = I * B * L * sin α => I = Fa / (B * L * sin α)
I = 0,75*10⁻⁶ Н / (2*10⁻³ Тл * 0,20 м * 1) ≈ 1,9*10⁻³ А = 1,9 мА

Answer 2

Calculation of Current in a Conductor in a Magnetic Field

To determine the current in a conductor placed in a uniform magnetic field, we can use the formula:

F = I * l * B * sin(θ)

Where: - F is the force acting on the conductor (given as 0.75 μN) - I is the current in the conductor (to be determined) - l is the length of the conductor (given as 20 cm or 0.2 m) - B is the magnetic field induction (given as 2 mT or 0.002 T) - θ is the angle between the magnetic field and the current (given as 90°)

We can rearrange the formula to solve for the current I:

I = F / (l * B * sin(θ))

Substituting the given values:

I = 0.75 μN / (0.2 m * 0.002 T * sin(90°))

Now, let's calculate the current.

Using the given values, the current in the conductor is approximately 1.875 A.

Please note that the angle between the magnetic field and the current is 90°, which means the sine of 90° is equal to 1. If the angle were different, the sine value would affect the calculation.