Question

Под действием силы 20Н пружина растянулась на 4см.Каков коэффициент жёсткости пружины?

Answer 1

по закону Гука

k=F/x= 20H/0.04м=500 Н/м

ОТВЕТ 500 Н/м

Answer 2

Calculating the Spring Constant (Stiffness) of a Spring

To calculate the spring constant (stiffness) of a spring, we can use the formula:

F = kx

Where: - F is the force applied to the spring (in Newtons, N) - k is the spring constant (in Newtons per meter, N/m) - x is the displacement of the spring from its equilibrium position (in meters, m)

Given: - Force applied, F = 20 N - Displacement, x = 0.04 m (converted from 4 cm to meters)

We can rearrange the formula to solve for the spring constant k:

k = F / x

Substitute the given values: k = 20 N / 0.04 m

Calculation

k = 500 N/m

So, the spring constant (stiffness) of the spring is 500 N/m.