Question

Прямолинейный медный проводник движется по проводящим рельсам со скоростью 45 см/с. Рельсы заземлены. Определить силу тока в этом проводнике, если магнитное поле, перпендикулярное плоскости движения, равно 0,2 Тл. Сечение проводника S = 0,5 мм2 , удельное сопротивление меди 0,018 Ом*мм2 /м Помогите пожалуйста решить задачу

Answer 1

$\mathcal{E} = BvL\\\\ I = \mathcal{E}/R = BvLS/\rho L = BvS/\rho = 2.5$

2.5 Ампера

Answer 2

Problem Analysis

We are given the following information: - A straight copper conductor is moving along conducting rails with a speed of 45 cm/s. - The rails are grounded. - The magnetic field perpendicular to the plane of motion is 0.2 T. - The cross-sectional area of the conductor is 0.5 mm^2. - The resistivity of copper is 0.018 Ω*mm^2/m.

We need to determine the current flowing through the conductor.

Solution

To solve this problem, we can use the formula for calculating the current in a moving conductor in a magnetic field:

I = (B * v * S) / (ρ)

Where: - I is the current flowing through the conductor, - B is the magnetic field strength, - v is the velocity of the conductor, - S is the cross-sectional area of the conductor, and - ρ is the resistivity of the conductor.

Let's substitute the given values into the formula and calculate the current.

Calculation

Given: - B = 0.2 T (magnetic field strength) - v = 45 cm/s = 0.45 m/s (velocity of the conductor) - S = 0.5 mm^2 = 0.5 * 10^(-6) m^2 (cross-sectional area of the conductor) - ρ = 0.018 Ω*mm^2/m (resistivity of copper)

Using the formula, we can calculate the current:

I = (0.2 T * 0.45 m/s * 0.5 * 10^(-6) m^2) / (0.018 Ω*mm^2/m)

Simplifying the expression:

I = 0.005 A

Therefore, the current flowing through the conductor is 0.005 A.

Answer

The current flowing through the straight copper conductor moving along the conducting rails with a speed of 45 cm/s, in a magnetic field of 0.2 T, is 0.005 A.