Question

К зажимам источника тока , ЭДС и внутреннее сопротивление которого 4,5 В и 1,5 Ом, присоединили резистор сопротивлением 7,5 Ом.Опредилить силу тока в цепи и падение напряжения внутри источника тока.

Answer 1

I=E/R+r = 4.5/(7.5+1.5)=4.5/9= 0.5 А
U=I*r=0.5*1.5= 0.75 B
ответ  сила тока 0.5 А, падение напряжения внутри источника 0.75 В

если ответ лучший отметь

Answer 2

Calculating Current and Voltage Drop in the Circuit

To calculate the current in the circuit and the voltage drop inside the current source, we can use the following formula:

Current (I) = Electromotive Force (EMF) / (Internal Resistance + External Resistance)

Given: - EMF (E) = 4.5 V - Internal Resistance (r) = 1.5 Ω - External Resistance (R) = 7.5 Ω

Using the formula, we can calculate the current (I) in the circuit:

I = E / (r + R)

I = 4.5 V / (1.5 Ω + 7.5 Ω) I = 4.5 V / 9 Ω I = 0.5 A

So, the current in the circuit is 0.5 A.

Next, to find the voltage drop inside the current source, we can use Ohm's law:

Voltage Drop (V) = Current (I) * Internal Resistance (r)

V = I * r V = 0.5 A * 1.5 Ω V = 0.75 V

Therefore, the voltage drop inside the current source is 0.75 V.

So, the current in the circuit is 0.5 A and the voltage drop inside the current source is 0.75 V.