Question

два велосипедиста двигались навстречу друг другу со скоростью 5м/с и 10 м/с.В момент наблодения второй был в 150м от моста, первый ехал по мосту

Answer 1

Дано V1=5 м/с    V2=10 м/с    L=150 м    t- ?    X- ?

Относительно  велосипедиста  V=V2-V1

t=L/V=L/(V2-V1)=150/5=30 с - время встречи

место встречи       X=V1*t=5*30=150 м  (от моста)

Answer 2

Meeting of Two Cyclists

When two cyclists are moving towards each other, their relative speed is the sum of their individual speeds. In this case, one cyclist is moving at 5 m/s and the other at 10 m/s.

Calculating the Meeting Point

To calculate the meeting point, we can use the concept of relative speed and the formula:

Meeting point = (distance traveled by the first cyclist + distance traveled by the second cyclist)

Given that the second cyclist was 150m away from the bridge at the moment of observation, we can calculate the distance traveled by the first cyclist using the formula:

Distance = speed × time

Let's denote: - Speed of the first cyclist as v1 = 5 m/s - Speed of the second cyclist as v2 = 10 m/s - Distance traveled by the first cyclist as d1 - Time taken by the first cyclist to reach the meeting point as t

The distance traveled by the first cyclist can be calculated as: d1 = v1 × t

The distance traveled by the second cyclist can be calculated as: d2 = v2 × t

Since the second cyclist was 150m away from the bridge, the total distance traveled by both cyclists is equal to 150m: d1 + d2 = 150

We can solve these equations to find the time taken by the first cyclist to reach the meeting point and then use this time to find the meeting point.

Let's calculate the meeting point using the given information.