Question

Какое количество теплоты поглащает при плавлении кусок олова массой 10грамм взятый при температуре плавления

Answer 1

Дано:

m=10 гр= 0,01 кг

l\(лямбда)= 59000Дж/кг

Q-?

Решение:

Q=l\*m = 0,01 кг * 59000 Дж/кг = 590 Дж

Answer 2

Calculating Heat Absorbed During Melting of Tin

To calculate the amount of heat absorbed during the melting of a 10-gram piece of tin at its melting temperature, we can use the formula:

Q = m * L

Where: - Q = heat absorbed or released - m = mass of the substance - L = latent heat of fusion

Mass of the Substance

The mass of the tin piece is given as 10 grams.

Latent Heat of Fusion for Tin

The latent heat of fusion for tin is required to calculate the heat absorbed during melting.

According to source the latent heat of fusion for tin is approximately 50 J/g.

Calculation

Using the given mass of the tin piece (m = 10g) and the latent heat of fusion for tin (L = 50 J/g), we can calculate the heat absorbed during the melting process:

Q = 10g * 50 J/g = 500 J

Therefore, the amount of heat absorbed during the melting of a 10-gram piece of tin at its melting temperature is approximately 500 Joules.