Question

Ширина лезвия лопаты 20см,толщина 3 мм.Человек нажимает на лопату с силой 30Н.Определите давление лопаты на почву.

Answer 1

S= ab
S= 0,2м* 0,003 м= 0,0006 м^2
p= F / S
p= 30 H / 0,0006=50 000 Па

Answer 2

Calculating Pressure Exerted by the Shovel

Given: - Blade width (w) = 20 cm - Blade thickness (t) = 3 mm - Force applied (F) = 30 N

First, we need to convert the blade thickness to meters: - Blade thickness (t) = 3 mm = 0.003 m

Calculating the Area of the Blade

The area of the blade in contact with the ground can be calculated using the formula: \[ \text{Area} = \text{width} \times \text{thickness} \]

Substitute the given values: \[ \text{Area} = 0.20 \, \text{m} \times 0.003 \, \text{m} \] \[ \text{Area} = 0.0006 \, \text{m}^2 \]

Determining the Pressure Exerted

The pressure exerted by the shovel on the ground can be calculated using the formula: \[ \text{Pressure} = \frac{\text{Force}}{\text{Area}} \]

Substitute the given values: \[ \text{Pressure} = \frac{30 \, \text{N}}{0.0006 \, \text{m}^2} \] \[ \text{Pressure} = 50000 \, \text{Pa} \]

The pressure exerted by the shovel on the ground is 50000 Pa.