Question

Серебряная ложка массой 50 г в тарелке с супом нагрелась на 20 градусов 1) для нагревания серебра массой 1 кг на 240 градусов потребеется 1 дж 2) для нагревания серебра массой 240 кг на 1 градус потребуется 1 дж теплоты 3) ложка получила от горячего супа 240 дж теплоты 4) удельная теплоемкость супа = удельной теплоемкости серебра

Answer 1

Думаю 3 ПРАВИЛЬНОЕ. но я в физике не профи

Answer 2

Calculation of Heat Transfer

To answer the given question, we need to calculate the heat transfer in different scenarios involving a silver spoon and soup. Let's break down the information provided:

1. The silver spoon with a mass of 50 g heated up by 20 degrees Celsius. 2. It is stated that it takes 1 J of energy to heat 1 kg of silver by 240 degrees Celsius. 3. It is also mentioned that it takes 1 J of energy to heat 240 kg of silver by 1 degree Celsius. 4. The spoon received 240 J of heat from the hot soup. 5. The specific heat capacity of the soup is equal to the specific heat capacity of silver.

Calculation 1: Heating 1 kg of Silver by 240 degrees Celsius

According to the given information, it takes 1 J of energy to heat 1 kg of silver by 240 degrees Celsius Therefore, to heat 1 kg of silver by 240 degrees Celsius, we would need 1 J of energy.

Calculation 2: Heating 240 kg of Silver by 1 degree Celsius

It is stated that it takes 1 J of energy to heat 240 kg of silver by 1 degree Celsius Therefore, to heat 240 kg of silver by 1 degree Celsius, we would need 1 J of energy.

Calculation 3: Heat Transfer to the Spoon

The spoon received 240 J of heat from the hot soup.

Calculation 4: Specific Heat Capacity of the Soup

It is mentioned that the specific heat capacity of the soup is equal to the specific heat capacity of silver.

Based on the given information, we can conclude that