Question

При равновесии рычага на его меньшее плечо действует сила 30Н,на большее 15Н.Длина меньшего плеча 5см.Определите длину большего плеча? Напишите с дано и решением

Answer 1

По закону рычага во сколько раз больше плечо рычага, во столько раз больше сил, прикладываемая к нему. Следовательно, отношение силы 1 (30Н) и силы 2 (15Н) равно отношению плеча 2 (Х) и плеча 1 (0.05м). Следовательно, 30:15=Х:0.05 ответ 40

Answer 2

F1=30H
F2=15H
L1=5см = 0,05 м
L2-?
F1*L1=F2*L2
L2=F1*L1 / F2
L2=30*0,05 / 15=1,5/15=0,1 м=10 см
Ответ:0,1 м.

Answer 3

Given Information:

- Force on the smaller arm of the lever: 30 N - Force on the larger arm of the lever: 15 N - Length of the smaller arm: 5 cm

Solution:

To determine the length of the larger arm of the lever, we can use the principle of moments. The principle of moments states that the sum of the moments acting on a body in equilibrium is zero.

The moment of a force is calculated by multiplying the magnitude of the force by the perpendicular distance from the point of rotation (fulcrum) to the line of action of the force.

Let's assume the length of the larger arm of the lever is x.

The moment of the force on the smaller arm (30 N) can be calculated as: Moment of the force on the smaller arm = Force on the smaller arm * Length of the smaller arm

The moment of the force on the larger arm (15 N) can be calculated as: Moment of the force on the larger arm = Force on the larger arm * Length of the larger arm

Since the lever is in equilibrium, the sum of the moments on both sides of the fulcrum is zero: Moment of the force on the smaller arm = Moment of the force on the larger arm

Using the given values, we can set up the equation: 30 N * 5 cm = 15 N * x

To solve for x, we can rearrange the equation: x = (30 N * 5 cm) / 15 N

Now, let's calculate the value of x: x = (30 N * 5 cm) / 15 N

Using the given values, we can calculate the length of the larger arm of the lever.

Answer: The length of the larger arm of the lever is 10 cm.

Calculation:

x = (30 N * 5 cm) / 15 N x = 150 N cm / 15 N x = 10 cm

Therefore, the length of the larger arm of the lever is 10 cm.