Question

Рычаг находится в равновесии под действием двух сил, первая из которых 4Н. Определите модуль второй силы, если плечо первой силы 15 см, а второй 10 см

Answer 1

F1L1=F2L2

4*0.15=F2*0.1

F2=4*0.15/0.1=6 Н

Answer 2

Calculation of the Second Force

To determine the magnitude of the second force, we can use the principle of moments. The principle of moments states that for an object in equilibrium, the sum of the clockwise moments is equal to the sum of the counterclockwise moments.

In this case, the lever is in equilibrium under the action of two forces. The first force is 4N, and its lever arm is 15cm. Let's denote the second force as F2, and its lever arm as 10cm.

According to the principle of moments, the clockwise moment produced by the first force is equal to the counterclockwise moment produced by the second force:

Clockwise moment = Counterclockwise moment

The clockwise moment is given by the product of the first force and its lever arm:

Clockwise moment = 4N * 15cm

The counterclockwise moment is given by the product of the second force and its lever arm:

Counterclockwise moment = F2 * 10cm

Setting the clockwise moment equal to the counterclockwise moment, we can solve for the magnitude of the second force (F2):

4N * 15cm = F2 * 10cm

Simplifying the equation:

4N * 15 = F2 * 10

To find the value of F2, we can rearrange the equation:

F2 = (4N * 15) / 10

Now we can calculate the value of F2:

F2 = (4N * 15) / 10

F2 = 60N

Therefore, the magnitude of the second force is 60N.