Question

До какой температуры нагрелась во время рабо­ты стальная фреза массой 1 кг, если после опуска­ния ее в калориметр температура 1 л воды повысилась с 11,3 °С до 30 °С? (Теплоемкость калориметра не учиты­вать.)

Answer 1

tx-искаемая температура

t1-температура, каторая установилась

t0-каторая была

 

Q1=c(воды)*m(воды)*(t1-t0)=c*p(води)*V(воды)*(t1-t0)=4200*1000*0.001*(30-11.3)=78540 Дж

Q1=Q2

Q2=c(стали)*m(стали)*(t1-tx)=500*1*(30-tx)=78540 Дж

tx=63540/500=127 С`

Answer 2

Calculation of the Temperature Increase

To calculate the temperature increase of the steel milling cutter during operation, we can use the formula:

Q = mcΔT

Where: - Q is the heat absorbed or released by the object (in this case, the milling cutter) - m is the mass of the object (1 kg) - c is the specific heat capacity of the object (assumed to be the same as water, 4.18 J/g°C) - ΔT is the change in temperature

In this case, the milling cutter is submerged in a calorimeter containing 1 liter of water. The temperature of the water increases from 11.3°C to 30°C. We need to find the change in temperature (ΔT) for the milling cutter.

Using the formula, we can rearrange it to solve for ΔT:

ΔT = Q / (mc)

Since the heat capacity of the calorimeter is not considered, we can assume that all the heat absorbed by the milling cutter is transferred to the water.

Let's calculate the change in temperature:

ΔT = Q / (mc) = (m * c * ΔT_water) / (m * c) = ΔT_water

Therefore, the change in temperature of the milling cutter is equal to the change in temperature of the water.

The change in temperature of the water is 30°C - 11.3°C = 18.7°C.

Therefore, the milling cutter also increases in temperature by 18.7°C during operation.

Answer

During operation, the steel milling cutter with a mass of 1 kg increases in temperature by 18.7°C when submerged in a calorimeter containing 1 liter of water, which increases in temperature from 11.3°C to 30°C