Question

Как изменится частота колебательного контура если электроемность уменьшится в 25 раз ,индуктивность увеличится в 16 раз

Answer 1

v1=1/(2*π*√(L*C))

v2=1/(2*π*√(16*L*C/25))=5/4*v1

Частота увеличится в 1,25 раза

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Answer 2

Changing Frequency of an Oscillating Circuit

When the capacitance decreases by a factor of 25 and the inductance increases by a factor of 16 in an oscillating circuit, the frequency of the circuit will change.

Calculating the New Frequency:

The frequency of an oscillating circuit can be calculated using the formula:

f = 1 / (2π√(LC))

Where: - f = frequency - L = inductance - C = capacitance

When the capacitance decreases by a factor of 25 and the inductance increases by a factor of 16, the new frequency can be calculated using the above formula.

Applying the Changes:

1. Capacitance Decreases by a Factor of 25: - The original capacitance, denoted as C, decreases by a factor of 25. - The new capacitance, denoted as C', can be calculated as C' = C / 25.

2. Inductance Increases by a Factor of 16: - The original inductance, denoted as L, increases by a factor of 16. - The new inductance, denoted as L', can be calculated as L' = 16 * L.

Calculating the New Frequency:

Using the new values of capacitance and inductance, the new frequency, denoted as f', can be calculated using the formula:

f' = 1 / (2π√(L'C'))

Now, let's calculate the new frequency based on the changes in capacitance and inductance.