Question

В эксперименте по теплообмену между двумя жидкостями неизвестная жидкость передала известной количество теплоты, равное 3600 Дж, остыв при этом на 15 С. Какова теплоемкость жидкости, если ее масса была равна 100г

Answer 1

Нужно 3600дж:15° ©:0,1 кг(Q=m×C(t2-t1))
c=Q:m:t
ответ: 2400 Дж\кг •°©

Answer 2

Calculation of Specific Heat Capacity

To calculate the specific heat capacity of the unknown liquid, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat transferred (in joules) - m is the mass of the liquid (in grams) - c is the specific heat capacity of the liquid (in J/g°C) - ΔT is the change in temperature of the liquid (in °C)

In this case, we know that the unknown liquid transferred 3600 J of heat and cooled down by 15°C. The mass of the liquid is given as 100 g.

Plugging in the values into the formula, we have:

3600 J = (100 g) * c * 15°C

To find the specific heat capacity (c), we can rearrange the equation:

c = 3600 J / (100 g * 15°C)

Calculating the value:

c = 2.4 J/g°C

Therefore, the specific heat capacity of the unknown liquid is 2.4 J/g°C.