Question

В сети с напряжением 127В параллельно включены 10 ламп. Определить сопротивление всей цепи и силу тока в ней, если сопротивление одной лампы 234 Ом, а проводов 2 Ом. ПОЖАЛУЙСТА, ПОМОГИТЕ, ОЧЕНЬ СРОЧНО :С

Answer 1

U=127 B    n=10    R1=234     R2=2     Ro=?   I=?

Ro=R1/n + R2=234/10+ 2=25.4 Ом

I=U/Ro=127/25.4=5 A

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Answer 2

Calculating Resistance and Current in the Circuit

To determine the resistance of the entire circuit and the current flowing through it, we can use the following formulas:

1. Total Resistance (R_total): - The total resistance of the circuit can be calculated using the formula: R_total = R_lamp + R_wires - Where R_lamp is the resistance of one lamp and R_wires is the resistance of the wires.

2. Current (I): - The current flowing through the circuit can be calculated using the formula: I = V / R_total - Where V is the voltage and R_total is the total resistance of the circuit.

Given: - Voltage (V) = 127V - Number of lamps = 10 - Resistance of one lamp (R_lamp) = 234Ω - Resistance of the wires (R_wires) = 2Ω

Calculations:

1. Total Resistance (R_total): - Using the formula: R_total = R_lamp + R_wires R_total = 10 * 234Ω + 2Ω R_total = 2340Ω + 2Ω R_total = 2342Ω

- Therefore, the total resistance of the circuit is 2342Ω.

2. Current (I): - Using the formula: I = V / R_total I = 127V / 2342Ω I ≈ 0.054A

- Therefore, the current flowing through the circuit is approximately 0.054A.

So, the total resistance of the circuit is 2342Ω and the current flowing through it is approximately 0.054A.