Question

Красная граница фотоэффекта для некоторого металла равна 2750 Å. Чему равно минимальное значение энергии фотона, вызывающего фотоэффект?

Answer 1

будет в ответе 4,5 эВ 

Answer 2

Calculating the Minimum Photon Energy for the Photoelectric Effect

The minimum energy required to cause the photoelectric effect can be calculated using the equation:

E = hf - φ

Where: - E = energy of the photon - h = Planck's constant (6.626 x 10^-34 J·s) - f = frequency of the incident light - φ = work function of the metal

Given that the red limit of the photoelectric effect for a certain metal is 2750 Å (angstroms), we can calculate the minimum energy of the photon required to cause the photoelectric effect for this metal.

Calculating the Frequency of the Incident Light

To calculate the frequency of the incident light, we can use the equation:

c = λf

Where: - c = speed of light in a vacuum (3.00 x 10^8 m/s) - λ = wavelength of the incident light

Converting the given wavelength of 2750 Å to meters: - 2750 Å = 2750 x 10^-10 m

Using the speed of light equation, we can solve for the frequency f.

Calculating the Minimum Photon Energy

Once we have the frequency of the incident light, we can use the equation E = hf - φ to calculate the minimum energy of the photon required to cause the photoelectric effect for the given metal.

Final Calculation

Let's perform the calculations step by step to find the minimum energy of the photon required for the photoelectric effect for the given metal.