Question

Рамка площадью 250 см^2 имеет 200 витков. чему равно амплитудное значение эдс, возникающей при вращении рамки с частотой 1200об/мин в однородном магнитном поле индукцией 0,2 тл) Помогите!

Answer 1

Em=B*S*2*pi*n=0,2*250*10^-4*6,28*20=0,63 В

Answer 2

Calculating the Amplitude of the Induced EMF

To calculate the amplitude of the electromotive force (EMF) induced when the frame rotates at a frequency of 1200 revolutions per minute (RPM) in a uniform magnetic field with an induction of 0.2 T, we can use the formula:

EMF = 2πfNAB

Where: - EMF is the electromotive force (in volts) - π is a mathematical constant approximately equal to 3.14159 - f is the frequency of rotation (in hertz) - N is the number of turns in the coil - A is the area of the coil (in square meters) - B is the magnetic field strength (in teslas)

Given: - Area of the frame (A) = 250 cm^2 = 0.025 m^2 - Number of turns (N) = 200 - Frequency (f) = 1200 RPM = 20 Hz - Magnetic field strength (B) = 0.2 T

Calculation

Using the given values in the formula: EMF = 2πfNAB EMF = 2 * 3.14159 * 20 * 200 * 0.025 * 0.2

Result

After calculation, the amplitude of the induced EMF is approximately 62.83 volts.

This calculation is based on the provided formula and the given values for the area, number of turns, frequency, and magnetic field strength.

Feel free to ask if you have further questions or need additional assistance!