Question

Камень был брошен вертикально вверх с начальной скоростью 5м/с и упал на землю через 3 с. С какой высоты был брошен камень?

Answer 1

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Answer 2

Calculation of the Initial Height

To determine the initial height from which the stone was thrown, we can use the equations of motion. The stone was thrown vertically upwards with an initial velocity of 5 m/s and it fell back to the ground after 3 seconds.

We can use the equation for displacement in vertical motion:

h = h0 + v0t - (1/2)gt^2

Where: - h is the final height (which is 0 since the stone falls back to the ground) - h0 is the initial height - v0 is the initial velocity (5 m/s) - t is the time taken (3 seconds) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values into the equation, we can solve for h0:

0 = h0 + (5 m/s)(3 s) - (1/2)(9.8 m/s^2)(3 s)^2

Simplifying the equation:

0 = h0 + 15 m - 44.1 m

h0 = 44.1 m - 15 m

h0 = 29.1 m

Therefore, the stone was thrown from a height of 29.1 meters.