Question

Куб с длиной ребра 20 см плавает в воде, наполовину погруженным в неё. Плотность воды 1000 кг/м в кубе . На куб действует выталкивающая сила, равная...Найти выталкивающую силу

Answer 1

Выталкивающая сила = Плотность жидкости * коэффициент g * объем погруженной части тела.
1)Найдем объем куба
V = a^3 = 0.2(метра)^3 = 0.008 метра^3
2)Найдем объем половины куба
он равен 0.004 метра^3
3)Выталкивающая сила = Плотность жидкости * коэффициент g * объем погруженной части тела.
Выталкивающая сила = 1000 кг/м в кубе * 10 H/кг * 0.004 метра^3 = 40H

Answer 2

Finding the Buoyant Force

To find the buoyant force acting on the cube, we can use the formula for buoyant force, which is given by F = ρ * g * V, where: - F is the buoyant force, - ρ is the density of the fluid (in this case, water), - g is the acceleration due to gravity, and - V is the volume of the fluid displaced by the object.

Calculating the Volume of the Displaced Water

The volume of the water displaced by the cube can be calculated using the formula V = a^2 * x, where: - a is the length of the side of the cube, and - x is the depth to which the cube is submerged.

Using the given values: - Length of the side of the cube, a = 20 cm, - Depth to which the cube is submerged, x = 10 cm.

Substituting these values into the formula, we get: V = (20 cm)^2 * 10 cm = 4000 cm^3 = 0.004 m^3.

Calculating the Buoyant Force

Now, we can calculate the buoyant force using the formula F = ρ * g * V. Given that the density of water is 1000 kg/m^3 and the acceleration due to gravity is 9.81 m/s^2, we can substitute these values into the formula: F = 1000 kg/m^3 * 9.81 m/s^2 * 0.004 m^3 = 39.24 N.

Therefore, the buoyant force acting on the cube is 39.24 N.