Question

Два точечных заряда находятся в вакууме на расстоянии 10 см, с такой же силой , как в диэлектрике на расстояние 5 см. определите диэлектрическую проницаемость диэлектрика?

Answer 1

Дано F1=F2      R1=10см     R2=5 см  e- ?

F1=F2
k*q1*q2/R1^2=k*q1*q2/e*R2^2
е=(R1/R2)^2=2^2=4

Ответ е=4

Answer 2

Calculating the Dielectric Permittivity

To calculate the dielectric permittivity of the material, we can use the formula for the force between two charges in a dielectric:

F = (1 / (4 * π * ε * ε0)) * (q1 * q2) / r^2

Where: - F is the force between the charges - π is a mathematical constant approximately equal to 3.14159 - ε is the dielectric constant - ε0 is the vacuum permittivity constant (approximately 8.854 x 10^-12 C^2/Nm^2) - q1 and q2 are the magnitudes of the charges - r is the separation between the charges

We are given that the force between the charges in the vacuum at a distance of 10 cm is the same as in the dielectric at a distance of 5 cm. Using this information, we can calculate the dielectric constant.

Calculation

Given: - Distance in vacuum, r_vacuum = 10 cm - Distance in dielectric, r_dielectric = 5 cm

We can use the ratio of the forces in vacuum and dielectric to find the dielectric constant:

F_vacuum / F_dielectric = (ε * ε0 * r_dielectric^2) / (r_vacuum^2)

Solving for ε:

ε = (F_vacuum / F_dielectric) * (r_vacuum^2) / (ε0 * r_dielectric^2)

Result

Using the given distances and the formula, the dielectric constant (ε) can be calculated.