Question

Плоский конденсатор емкостью о,о2мкФ соединили с источником тока, в результате чего он приобрелз-аряд 2*10^-8Кл.Найти значение напряженности поля между пластинами конденсатора, если расстояние между ними 1 мл

Answer 1

C=q/U   U=q/C=2*10^-8/2*10^-5=1*10^-3
E=U/d=1*10^-3/1*10^-3=1в/м 

Answer 2

To find the value of the electric field between the plates of a capacitor, we can use the formula:

E = Q / (ε₀ * A)

Where: - E is the electric field strength (in N/C or V/m) - Q is the charge on the capacitor plates (in C) - ε₀ is the permittivity of free space (approximately 8.85 x 10^-12 F/m) - A is the area of the capacitor plates (in m²)

In this case, the charge on the capacitor plates is given as 2 * 10^-8 C, and the capacitance is given as 0.02 μF (which is equal to 2 * 10^-8 F). The distance between the plates is given as 1 mm (which is equal to 0.001 m).

To find the area of the capacitor plates, we can rearrange the formula for capacitance:

C = ε₀ * A / d

Where: - C is the capacitance (in F) - d is the distance between the plates (in m)

Rearranging this formula, we can solve for A:

A = C * d / ε₀

Substituting the given values:

A = (2 * 10^-8 F) * (0.001 m) / (8.85 x 10^-12 F/m)

Calculating this expression gives us the value of A.

Now, we can substitute the values of Q, A, and ε₀ into the formula for electric field strength to find the value of E.

Let me calculate that for you.