Question

Определите плотность j в в проводнике длиной 10 м с удельным сопротивлением 5,5*10^(-7)(степень) Ом*м если напряжение на его концах 10 в

Answer 1

J=I/s (1)
i=U/R (2)
R=p*L/s 3)
Подставляя 2 и 3 в 1 получим: j=U/p*L=10/5,5*10^-7*10=18*10^5 А\м2

Answer 2

Calculating the Density of Current in a Conductor

To calculate the density of current (J) in a conductor with a length of 10 m and a specific resistance of 5.5 x 10^(-7) Ohm*m, given a voltage of 10 V across its ends, we can use the formula:

J = I / A

Where: - J = current density (A/m^2) - I = current (A) - A = cross-sectional area (m^2)

First, let's calculate the current (I) using Ohm's law:

I = V / R

Where: - V = voltage (V) - R = resistance (Ohm)

Then, we can calculate the cross-sectional area (A) of the conductor using the formula:

A = ρ * L

Where: - ρ = specific resistance (Ohm*m) - L = length of the conductor (m)

Let's proceed with the calculations.

Calculating the Current

Using Ohm's law: I = V / R I = 10 V / 5.5 x 10^(-7) Ohm*m I ≈ 1.818 x 10^7 A

Calculating the Cross-Sectional Area

Using the formula: A = ρ * L A = 5.5 x 10^(-7) Ohm*m * 10 m A = 5.5 x 10^(-6) m^2

Calculating the Current Density

Using the formula: J = I / A J = (1.818 x 10^7 A) / (5.5 x 10^(-6) m^2) J ≈ 3.305 x 10^12 A/m^2

Therefore, the density of current (J) in the conductor is approximately 3.305 x 10^12 A/m^2.