Question

Грузик, колеблющийся на пружине, за 8 секунд совершил 32 колебания. Найдите период и частоту колебаний.(Полное решение)

Answer 1

Формула частоты колебанийV=$\frac{N}{t}$
То есть кол-во колебаний делить на время колебаний.
V=$\frac{32}{8}$=4
Формула периода колебанийT=$\frac{1}{V}$ (Период колебаний связан соотношением взаимной обратности с частотой)
T=$\frac{1}{4}$ = 0.25

Answer 2

Problem Analysis

We are given that a truck oscillating on a spring completes 32 oscillations in 8 seconds. We need to find the period and frequency of the oscillations.

Solution

The period of an oscillation is the time taken to complete one full cycle of oscillation. The frequency of an oscillation is the number of cycles completed per unit time.

To find the period, we divide the total time taken by the number of oscillations: Period (T) = Total time / Number of oscillations

To find the frequency, we divide the number of oscillations by the total time: Frequency (f) = Number of oscillations / Total time

Let's calculate the period and frequency using the given values.

Calculation

Given: Total time (t) = 8 seconds Number of oscillations (n) = 32

Using the formulas mentioned above: Period (T) = t / n Frequency (f) = n / t

Substituting the given values: Period (T) = 8 / 32 Frequency (f) = 32 / 8

Simplifying the equations: Period (T) = 0.25 seconds Frequency (f) = 4 Hz

Answer

The period of the oscillations is 0.25 seconds and the frequency is 4 Hz.

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