Question

Очень нужно.... Помогите, пожалуйстаАвтомобиль массой 1000 кг, двигаясь равноускоренно из состояния покоя, за 10 с отъезжает на200 м. Определите работу силы тяги, если коэффициент трения равен 0,05.

Answer 1

V0=0  
Сделай рисунок,получишь: Fт=Fтр+ma
N=mg
a=2S/t^2=4м/с^2
Fт=m(a+мюg)=4500H
A=FS=900кH

Answer 2

Calculating the Work Done by the Driving Force

To calculate the work done by the driving force, we can use the formula:

Work = Force × Distance

Given: - Mass of the car (m) = 1000 kg - Distance traveled (d) = 200 m - Time taken (t) = 10 s - Coefficient of friction (μ) = 0.05

First, let's calculate the acceleration of the car using the formula:

Distance = Initial Velocity × Time + (1/2) × Acceleration × Time^2

We can rearrange this formula to solve for acceleration:

Acceleration = 2 × (Distance - Initial Velocity × Time) / Time^2

Given that the car starts from rest (initial velocity = 0 m/s), the equation simplifies to:

Acceleration = 2 × Distance / Time^2

Let's calculate the acceleration: ``` Acceleration = 2 × 200 m / (10 s)^2 Acceleration = 2 × 200 m / 100 s^2 Acceleration = 4 m/s^2 ```

Now that we have the acceleration, we can calculate the driving force using Newton's second law:

Force = Mass × Acceleration

Let's calculate the driving force: ``` Force = 1000 kg × 4 m/s^2 Force = 4000 N ```

Now, to calculate the work done by the driving force, we can use the formula:

Work = Force × Distance

Let's calculate the work done by the driving force: ``` Work = 4000 N × 200 m Work = 800,000 J ```

Conclusion

The work done by the driving force is 800,000 joules.