Question

Автомобиль массой 1000 кг движется со скоростью 72км/ч по выпуклому мосту радиусом 40м. С какой силой автомобиль действует на мост в верхней его точке? плиз((

Answer 1

72 км/ч= 20 м/сF= m ( g+a)   a= V^2 / R        a= 400/ 80= 5 м/с^2F= 1000* ( 10+5)= 15000 H

Answer 2

I can help you with your physics question.

The force that the car exerts on the bridge at the highest point is equal to the difference between its weight and the centrifugal force. The weight is given by $$W = mg$$ where $$m$$ is the mass of the car and $$g$$ is the gravitational acceleration. The centrifugal force is given by $$F_c = \frac{mv^2}{R}$$ where $$v$$ is the speed of the car and $$R$$ is the radius of the bridge. Therefore, the force that the car exerts on the bridge is $$F = W - F_c = mg - \frac{mv^2}{R}$$

To find the numerical value of this force, we need to convert the units to SI units. The mass of the car is 1000 kg, the speed of the car is 72 km/h, which is equivalent to 20 m/s, and the radius of the bridge is 40 m. The gravitational acceleration is approximately 9.8 m/s^2. Plugging these values into the formula, we get $$F = 1000 \times 9.8 - \frac{1000 \times 20^2}{40} = 9800 - 10000 = -200$$

The negative sign means that the force is directed downwards, opposite to the normal force of the bridge. The magnitude of the force is 200 N. This is the answer to your question. You can find more details and examples on this topic in the following sources: , , . I hope this helps. Have a nice day.