Question

Движение материальной точки задано уравнением:х=9t-0,5t^2. Перемешение за 2с после начала движения равно

Answer 1

1 X(0)=0
2 X(2)=9*2 -0,5*4=18-2=16 м
3 Sx=16 -0=16 м - ответ

Answer 2

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Your question is about the displacement of a material point whose motion is given by the equation $x=9t-0.5t^2$. The displacement is the change in position of the point, which can be found by subtracting the initial position from the final position. The initial position is given by $x_0=x(0)=9\cdot 0-0.5\cdot 0^2=0$. The final position is given by $x_2=x(2)=9\cdot 2-0.5\cdot 2^2=14$. Therefore, the displacement is $x_2-x_0=14-0=14$ meters. This means that the point moved 14 meters to the right from its initial position.

You can find more information about the motion of a material point on [this page](https://ru.wikipedia.org/wiki/%D0%9C%D0%B0%D1%82%D0%B5%D1%80%D0%B8%D0%B0%D0%BB%D1%8C%D0%BD%D0%B0%D1%8F_%D1%82%D0%BE%D1%87%D0%BA%D0%B0) or [this page](https://obrazovaka.ru/fizika/uravnenie-dvizheniya-tochki.html). You can also check your answer with [this solution](https://reshak.ru/otvet/otvet10.php?otvet1=320&var=1var). I hope this helps.