Question

Какое количество теплоты поглощает проплавлении кусок свинца массой 1 кг начальная температура которого 27 градусов по цельсии олово массой 10 г взятого при температуре 32 градуса по цельсии?

Answer 1

Температура плавания свинца и  есть 327 C

Answer 2

Calculation of Heat Absorbed during Lead Melting

To calculate the amount of heat absorbed during the melting of a piece of lead, we can use the formula:

Q = m * c * ΔT

Where: - Q is the amount of heat absorbed (in joules) - m is the mass of the substance (in kilograms) - c is the specific heat capacity of the substance (in joules per kilogram per degree Celsius) - ΔT is the change in temperature (in degrees Celsius)

In this case, we have a piece of lead with a mass of 1 kg and an initial temperature of 27 degrees Celsius. We also have a piece of tin with a mass of 10 g and an initial temperature of 32 degrees Celsius.

First, let's convert the mass of tin from grams to kilograms: - Mass of tin = 10 g = 0.01 kg

Next, we need to find the specific heat capacity of lead. Unfortunately, the specific heat capacity of lead was not provided in the search results. However, we can assume that the specific heat capacity of lead is approximately 130 J/(kg·°C) based on general knowledge.

Using the formula, we can calculate the amount of heat absorbed during the melting of the lead:

Q = m * c * ΔT Q = 1 kg * 130 J/(kg·°C) * (0°C - 27°C) Q = -3510 J

Therefore, the amount of heat absorbed during the melting of the lead is -3510 joules.

Please note that the negative sign indicates that heat is being released during the process of lead melting.