
Какого давление в Марианской впадине,глубина которой 11 км? Не забудь,что вода в океане соленая.
Помогите пожалуйста)

Ответы на вопрос

pв=1030 кг/м3
g=10
h=11км=11000м
P=pgh=11000 x 10 x 1030=113300000Па



Pressure in the Mariana Trench
The Mariana Trench is the deepest part of the world's oceans, located in the western Pacific Ocean. It reaches a maximum depth of approximately 11 kilometers (6.8 miles). At such depths, the pressure is extremely high due to the weight of the water column above.
The pressure in the Mariana Trench can be calculated using the hydrostatic pressure formula, which states that pressure increases with depth. The formula is given by:
Pressure = Density x Gravity x Depth
In this case, the density of seawater and the acceleration due to gravity are the key factors. The density of seawater varies slightly depending on factors such as temperature and salinity. The average density of seawater is around 1027 kilograms per cubic meter (kg/m³).
The acceleration due to gravity is approximately 9.8 meters per second squared (m/s²).
Using these values, we can calculate the pressure at a depth of 11 kilometers in the Mariana Trench.
Pressure = 1027 kg/m³ x 9.8 m/s² x 11000 meters
Calculating this, we find that the pressure in the Mariana Trench at a depth of 11 kilometers is approximately 1076 megapascals (MPa) or 10,760 times atmospheric pressure.
Please note that the actual pressure in the Mariana Trench may vary slightly due to factors such as temperature and salinity variations. However, the calculated value provides a good estimate of the pressure at that depth.


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