
Молот масою 350 кг падає з висоти 2 м на кусок сталі масою 2 кг.На скільки градусів нагріється
виріб, коли він дістає 50 % теплоти, що виділяється під час удару?

Ответы на вопрос

h=2 м
m2=2 кг
КПД=0,5
с2=460 Дж/кг*С
КПД*Ep1=Q2
КПД*m1gh1=c2m2t2
t2=КПД*m1gh1/c2m2
t2=0,5*350*2*10/460*2=3,8 С



Calculation of Temperature Increase
To calculate the temperature increase of the object when it absorbs 50% of the heat generated during the impact, we can use the equation:
Q = mcΔT
Where: - Q is the heat absorbed by the object - m is the mass of the object - c is the specific heat capacity of the object's material - ΔT is the change in temperature
In this case, the mass of the object (m) is 2 kg, and the heat absorbed (Q) is 50% of the heat generated during the impact. We need to find the change in temperature (ΔT).
To find the specific heat capacity (c) of the object's material, we can refer to relevant search results.
Specific Heat Capacity of Steel
According to search results, the specific heat capacity of steel can vary depending on the type of steel. However, a commonly used value for the specific heat capacity of steel is around 0.49 J/g°C [[1]].
Calculation
To calculate the change in temperature (ΔT), we can rearrange the equation:
ΔT = Q / (mc)
Given that Q is 50% of the heat generated during the impact, we can calculate Q as follows:
Q = 0.5 * heat generated during impact
The heat generated during the impact can be calculated using the equation:
heat generated during impact = m * g * h
Where: - m is the mass of the falling object (350 kg) - g is the acceleration due to gravity (9.8 m/s^2) - h is the height from which the object falls (2 m)
Substituting the values into the equation, we can calculate the heat generated during the impact.
Finally, we can substitute the values of Q, m, c, and calculate the change in temperature (ΔT).
Please note that the specific heat capacity of steel may vary, so the calculated value should be considered an approximation.
Let's perform the calculations.


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