Question

Как тут найти массу, если известно, что mgh=Nt И как получить из этого m=(Nt)/(gh)? Мощность двигателя подъемной машины равна 4 кВт. Какой груз она может поднять на высоту 15 м в течение 2 мин?

Answer 1

N=4 кВт=4000 Вт           мощность:
t=2 мин=120 c                     N=A/t=mgh/t   ⇒   m=Nt/gh;
h=15 м                                 m=4000*120/10*15=3200 кг;
g=10 м/с²                            
______________                 Ответ: m=3200 кг.
m-?

Answer 2

Finding Mass using the formula mgh = Nt

To find the mass (m) when the force (N), time (t), height (h), and gravitational acceleration (g) are known, you can use the formula mgh = Nt. This formula relates the force exerted on an object to its mass, height, and the time it takes to exert that force.

To solve for mass (m), you can rearrange the formula as follows:

m = (Nt) / (gh)

Where: - m is the mass of the object - N is the force exerted on the object - t is the time taken to exert the force - g is the gravitational acceleration - h is the height

Calculating the Load a Lift Machine Can Carry

To calculate the load that a lift machine can carry, you need to know the power of the lift machine and the height it needs to lift the load.

In this case, the power of the lift machine is given as 4 kW (kilowatts), and the height it needs to lift the load is 15 m (meters). The time taken to lift the load is given as 2 minutes.

To calculate the load, you can use the formula:

Load = (Power * Time) / (Height * Gravitational Acceleration)

Substituting the given values:

Load = (4 kW * 2 min) / (15 m * 9.8 m/s^2)

Note: It is important to convert the units to a consistent system. In this case, we will convert the power from kilowatts to watts and the time from minutes to seconds.

Load = (4,000 W * 120 s) / (15 m * 9.8 m/s^2)

Simplifying the equation:

Load = 32,000 Ws / 147 m/s^2

Load ≈ 217.69 kg

Therefore, the lift machine can carry a load of approximately 217.69 kg to a height of 15 m in 2 minutes.

Please note that the above calculation assumes ideal conditions and does not take into account factors such as friction or the efficiency of the lift machine.