Question

Граната, летящая со скоростью 15 м/c разорвалась на 2 осколка, массами 5 и 15 кг. Скорость большего возросла до 30 м/с по направлению движенияОпределить графический импульс меньшего осколка.Найти скорость движения меньшего осколка.В каком направлении он будет двигаться?

Answer 1

Не знаю, что такое "графический импульс меньшего осколка"
m1 = 15   m2 = 5   v0 = 15   v1 = 30,   v2 = ?
(m1+m2)*V0 = m1v1 + m2v2
v2 = ((m1+m2)*V0 - m1v1))/m2 = -30 м/с
скорость по модулю = 30, знак показывает направление. стало быть, осколок полетел назад. против движения гранаты        

Answer 2

Calculation of the graphical impulse of the smaller fragment:

To determine the graphical impulse of the smaller fragment, we can use the principle of conservation of momentum. The total momentum before the explosion is equal to the total momentum after the explosion.

The momentum of an object is given by the product of its mass and velocity. Let's denote the mass of the smaller fragment as m1 and its velocity as v1. The mass of the larger fragment is m2, and its velocity is v2.

Before the explosion, the total momentum is the sum of the momentum of the smaller fragment and the momentum of the larger fragment:

m1 * v1 + m2 * v2

After the explosion, the larger fragment's velocity increases to 30 m/s in the direction of motion. Therefore, the smaller fragment's velocity will be in the opposite direction.

Using the principle of conservation of momentum, we can set up the following equation:

m1 * v1 + m2 * v2 = m1 * (-v1) + m2 * 30

Since the mass of the smaller fragment is given as 5 kg and the mass of the larger fragment is given as 15 kg, we can substitute these values into the equation:

5 * v1 + 15 * v2 = 5 * (-v1) + 15 * 30

Simplifying the equation:

10 * v1 + 15 * v2 = 15 * 30

Now we can solve this equation to find the value of the graphical impulse of the smaller fragment.

Calculation of the velocity of the smaller fragment:

To find the velocity of the smaller fragment, we can use the principle of conservation of momentum. The total momentum before the explosion is equal to the total momentum after the explosion.

Using the equation from the previous calculation:

m1 * v1 + m2 * v2 = m1 * (-v1) + m2 * 30

We can substitute the values of m1, m2, and v2 into the equation:

5 * v1 + 15 * 30 = 5 * (-v1) + 15 * 30

Simplifying the equation:

10 * v1 = 0

Since the mass of the smaller fragment is 5 kg, we can conclude that the velocity of the smaller fragment is 0 m/s.

Direction of motion of the smaller fragment:

Since the velocity of the smaller fragment is 0 m/s, it means that the smaller fragment will not be moving in any particular direction. It will remain stationary after the explosion.

Therefore, the smaller fragment will not have any specific direction of motion.

Please note that the calculations and conclusions made above are based on the information provided in the question.