Question

Две одинаковые частицы движутся по взаимно перпендикулярным направлениям. Модуль скорости первой частицы v1 = 3.6 м/c. В результате столкновения вторая частица останавливается, а первая продолжает движение со скоростью, модуль которой v' = 6.0 м/c. Определите модуль скорости второй частицы до столкновения.

Answer 1

7.5 м/с по закону сохранения импульса- теорема Пифагора вам в помощь в данном случае.Теорем:R=√p²+(¾)²p²=√25/16p²=5/4p или 1,25p

Answer 2

Problem Analysis

We have two particles moving in mutually perpendicular directions. The first particle has an initial velocity of v1 = 3.6 m/s and after the collision, the second particle comes to a stop while the first particle continues moving with a velocity of v' = 6.0 m/s. We need to determine the magnitude of the velocity of the second particle before the collision.

Solution

Let's assume the initial velocity of the second particle is v2.

According to the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity.

Before the collision: - Momentum of the first particle: m1 * v1 - Momentum of the second particle: m2 * v2

After the collision: - Momentum of the first particle: m1 * v' - Momentum of the second particle: m2 * 0 (since it comes to a stop)

Since the total momentum before and after the collision is the same, we can write the equation:

m1 * v1 + m2 * v2 = m1 * v' + m2 * 0

Since the second particle comes to a stop, we can simplify the equation to:

m1 * v1 = m1 * v'

Now we can solve for v2:

v2 = (m1 * v' - m1 * v1) / m2

To find the value of v2, we need the masses of the particles. Unfortunately, the masses are not provided in the given information. Therefore, we cannot determine the magnitude of the velocity of the second particle before the collision without knowing the masses of the particles.

Please provide the masses of the particles so that we can calculate the value of v2.