Question

. Человек массой 70 кг поднимается в лифте, движущемся равнозамедленно вертикально вверх с ускорением 1 м/с2. Определить силу давления человека на пол кабины лифта.

Answer 1

Мб не силу давления, а давление?

Answer 2

Calculation of the Pressure Force on the Floor of the Elevator

To determine the force of pressure exerted by a person with a mass of 70 kg on the floor of an elevator moving vertically upwards with an acceleration of 1 m/s^2, we can use Newton's second law of motion.

According to Newton's second law, the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the force of pressure exerted by the person on the floor of the elevator is equal to the product of the person's mass and the acceleration of the elevator.

Using the given values: - Mass of the person (m) = 70 kg - Acceleration of the elevator (a) = 1 m/s^2

We can calculate the force of pressure (F) using the formula:

F = m * a

Substituting the given values into the formula:

F = 70 kg * 1 m/s^2

Calculating the result:

F = 70 N

Therefore, the force of pressure exerted by the person on the floor of the elevator is 70 Newtons (N)