Question

Кусок льда весит в керосине 0,5 Н. Сколько будет весить этот кусок льда, если его наполовину погрузить в воду? Плотность керосина 800 кг/м3, плотность льда 900 кг/м3, плотность воды 1000 кг/м3.

Answer 1

0.5 Н = Vльда * 900* 10- V льда * 800 * 10( по архимеду) 
V льда(9000-8000)= 0.5
V льда = 0.0005 м^3
P льда в воде = mg - Fарх = Vльда * 900 * 10 - 1/2*V льда * 1000 * 10=
Vльда(9000-5000)= 0.0005 * 4000 = 2 Н
Ответ: 2 Н

Answer 2

Calculation of the Weight of the Ice in Kerosene

To calculate the weight of the ice in kerosene when it is partially submerged in water, we need to consider the densities of kerosene, ice, and water.

Given: - Density of kerosene = 800 kg/m^3- Density of ice = 900 kg/m^3- Density of water = 1000 kg/m^3 Let's assume the initial weight of the ice in kerosene is W kg.

When the ice is partially submerged in water, it displaces an amount of kerosene equal to its own weight. Therefore, the weight of the displaced kerosene is also W kg.

The remaining weight of the ice in kerosene is equal to the initial weight minus the weight of the displaced kerosene.

The weight of the ice in kerosene when it is partially submerged in water can be calculated using the following equation:

Weight of ice in kerosene = Initial weight - Weight of displaced kerosene

Let's calculate the weight of the ice in kerosene.

Calculation Steps:

1. Calculate the weight of the displaced kerosene: - Weight of displaced kerosene = Density of kerosene * Volume of displaced kerosene

2. Calculate the volume of the displaced kerosene: - Volume of displaced kerosene = Volume of ice submerged in water

3. Calculate the volume of the ice submerged in water: - Volume of ice submerged in water = Volume of ice * Fraction submerged in water

4. Calculate the volume of the ice: - Volume of ice = Weight of ice / Density of ice

5. Calculate the fraction submerged in water: - Fraction submerged in water = Volume of ice submerged in water / Volume of ice

6. Calculate the weight of the ice in kerosene: - Weight of ice in kerosene = Initial weight - Weight of displaced kerosene

Now, let's perform the calculations.

Calculation:

Given: - Density of kerosene = 800 kg/m^3 - Density of ice = 900 kg/m^3 - Density of water = 1000 kg/m^3

Let's assume the initial weight of the ice in kerosene is W kg.

1. Calculate the weight of the displaced kerosene: - Weight of displaced kerosene = Density of kerosene * Volume of displaced kerosene

2. Calculate the volume of the displaced kerosene: - Volume of displaced kerosene = Volume of ice submerged in water

3. Calculate the volume of the ice submerged in water: - Volume of ice submerged in water = Volume of ice * Fraction submerged in water

4. Calculate the volume of the ice: - Volume of ice = Weight of ice / Density of ice

5. Calculate the fraction submerged in water: - Fraction submerged in water = Volume of ice submerged in water / Volume of ice

6. Calculate the weight of the ice in kerosene: - Weight of ice in kerosene = Initial weight - Weight of displaced kerosene

Let's substitute the given values into the equations and perform the calculations.

1. Calculate the weight of the displaced kerosene: - Weight of displaced kerosene = 800 kg/m^3 * Volume of displaced kerosene

2. Calculate the volume of the displaced kerosene: - Volume of displaced kerosene = Volume of ice submerged in water

3. Calculate the volume of the ice submerged in water: - Volume of ice submerged in water = Volume of ice * Fraction submerged in water

4. Calculate the volume of the ice: - Volume of ice = Weight of ice / 900 kg/m^3

5. Calculate the fraction submerged in water: - Fraction submerged in water = Volume of ice submerged in water / Volume of ice

6. Calculate the weight of the ice in kerosene: - Weight of ice in kerosene = W kg - Weight of displaced kerosene

Please provide the initial weight of the ice in kerosene (W kg) to proceed with the calculations.