Question

Срочно !!! заплачу много) К городской сети переменного тока с эффективным значением напряжения U=127 B присоединена цепь, состоящая из последовательно включенных активного сопротивления R=199 Ом и конденсатора емкостью С=40 мкФ. Определите амплитуду силы тока в цепи.

Answer 1

1) найти амплитуду напряжения

$Um=U\sqrt{2}$         180В

2)закон ома для R-C цепи

в знаменателе из-под корня приблизительно 200

поэтому 180/200=0,9А

 

Answer 2

Calculation of Current Amplitude in the Circuit

To determine the amplitude of the current in the circuit, we can use Ohm's Law and the impedance of the circuit components. The impedance of a resistor is given by its resistance (R), while the impedance of a capacitor is given by the reciprocal of the product of the angular frequency (ω) and the capacitance (C).

Let's calculate the impedance of the capacitor first:

Impedance of the capacitor (Zc) = 1 / (ωC)

The angular frequency (ω) can be calculated using the formula:

Angular frequency (ω) = 2πf

where f is the frequency of the alternating current.

Since the problem statement does not provide the frequency, we will assume a standard frequency of 50 Hz.

Angular frequency (ω) = 2π * 50 Hz

Now, let's calculate the impedance of the capacitor:

Impedance of the capacitor (Zc) = 1 / (2π * 50 Hz * 40 μF)

Next, we can calculate the total impedance (Z) of the circuit by summing the impedance of the resistor (R) and the impedance of the capacitor (Zc):

Total impedance (Z) = R + Zc

Finally, we can calculate the amplitude of the current (I) using Ohm's Law:

Amplitude of current (I) = U / Z

where U is the effective value of the voltage in the circuit.

Now, let's substitute the given values into the formulas and calculate the amplitude of the current in the circuit.

Calculation Steps:

1. Calculate the angular frequency (ω): - Angular frequency (ω) = 2π * 50 Hz

2. Calculate the impedance of the capacitor (Zc): - Impedance of the capacitor (Zc) = 1 / (2π * 50 Hz * 40 μF)

3. Calculate the total impedance (Z): - Total impedance (Z) = 199 Ω + Zc

4. Calculate the amplitude of the current (I): - Amplitude of current (I) = 127 V / Z

Let's perform the calculations:

Calculation Results:

1. Angular frequency (ω): - Angular frequency (ω) = 2π * 50 Hz = 314.16 rad/s

2. Impedance of the capacitor (Zc): - Impedance of the capacitor (Zc) = 1 / (2π * 50 Hz * 40 μF) ≈ 397.89 Ω

3. Total impedance (Z): - Total impedance (Z) = 199 Ω + 397.89 Ω ≈ 596.89 Ω

4. Amplitude of the current (I): - Amplitude of current (I) = 127 V / 596.89 Ω ≈ 0.213 A

Therefore, the amplitude of the current in the circuit is approximately 0.213 A.