Question

Колебательный контур состоит из конденсатора индуктивностью в мкФ и катушки 0,03 Гн . Вычислите период колебания в контуре

Answer 1

Если я правильно понял, то
C = 8 мкФ = 8*10⁻⁶ Ф
L=0,03 Гн
_________
T - ?

По формуле Томсона:
T = 2*π*√(L*C) = 2*3,14*√(0,03*8*10⁻⁶) ≈ 0,003 с

Answer 2

Calculation of the Period of Oscillation in the Circuit

To calculate the period of oscillation in the given circuit, we need to know the values of the capacitor and inductor. From the information provided, the circuit consists of a capacitor with a capacitance of μF and an inductor with an inductance of 0.03 H.

The period of oscillation in an LC circuit can be calculated using the formula:

T = 2π√(LC)

where T is the period, L is the inductance, and C is the capacitance.

Substituting the given values into the formula, we have:

T = 2π√(0.03 * C)

Unfortunately, the value of the capacitance (C) is not provided in the question. Therefore, we cannot calculate the period of oscillation in the circuit without this information.

If you have the value of the capacitance, please provide it so that we can calculate the period of oscillation accurately.