Question

Шар упал с высоты 80 м . Какое перемещение совершил шар за последнюю секунду своего движения?Напишите с дано пожалуйста.

Answer 1

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Answer 2

Calculation of the displacement of the ball in the last second of its motion

To calculate the displacement of the ball in the last second of its motion, we need to determine its final velocity and initial velocity.

Given: - Initial height (h) = 80 m

To find the final velocity (Vf), we can use the equation of motion:

Vf^2 = Vi^2 + 2gh

Where: - Vf is the final velocity - Vi is the initial velocity (which is 0 in this case, as the ball is dropped) - g is the acceleration due to gravity (approximately 9.8 m/s^2) - h is the height

Substituting the given values into the equation, we have:

Vf^2 = 0 + 2 * 9.8 * 80

Simplifying the equation, we get:

Vf^2 = 1568

Taking the square root of both sides, we find:

Vf ≈ 39.6 m/s

Now that we have the final velocity, we can calculate the displacement (d) using the equation:

d = Vf * t

Where: - d is the displacement - Vf is the final velocity - t is the time (which is 1 second in this case)

Substituting the values, we have:

d = 39.6 * 1

Therefore, the displacement of the ball in the last second of its motion is approximately 39.6 meters.

Please note that the calculations assume no air resistance and a constant acceleration due to gravity.