Question

Температура нагревателя 200°C. Определить кпд теплового двигателя и температуру холодильника, если за счёт каждого кДж тепла, совершается 320 Дж работы

Answer 1

Т1=473К,Q1=1000 Дж, А=Q1-Q2=320Дж, Q2=1000-320=680 Дж,кпд =А/Q1=(320/1000)*100%=32%=(T1-T2)100%/T1; T2=473-473*0,32=320,96K=321,64K=48,64C

Answer 2

Calculation of Thermal Engine Efficiency and Refrigerator Temperature

To determine the thermal engine efficiency and the temperature of the refrigerator, given that 320 J of work is performed for every kilojoule (kJ) of heat, we need to use the equation for thermal efficiency:

Thermal Efficiency (η) = (Useful Work Output / Heat Input) x 100%

Let's assume that the heat input to the thermal engine is Q.

The useful work output is given as 320 J, and the heat input is Q in kJ.

To find the heat input, we need to convert the work output from joules to kilojoules:

320 J = 0.32 kJ

Now we can calculate the thermal efficiency:

η = (0.32 kJ / Q) x 100%

To find the temperature of the refrigerator, we need to use the equation for the efficiency of a refrigerator:

Refrigerator Efficiency (η_ref) = (Useful Cooling Output / Work Input) x 100%

The useful cooling output is the heat removed from the refrigerator, which is equal to the heat input to the thermal engine.

The work input is the work done on the refrigerator, which is equal to the work output of the thermal engine.

Let's assume that the temperature of the refrigerator is T.

Now we can calculate the refrigerator efficiency:

η_ref = (Q / 0.32 kJ) x 100%

To find the temperature of the refrigerator, we need to use the equation for the efficiency of a refrigerator:

η_ref = (Q / 0.32 kJ) x 100%

To find the temperature of the refrigerator, we need to use the equation for the efficiency of a refrigerator:

η_ref = (Q / 0.32 kJ) x 100%

Now we can solve for T:

T = 200°C - (η_ref x 200°C)

Let's calculate the values using the given information:

- Temperature of the heater: 200°C - Work output: 320 J - Heat input: 0.32 kJ

First, let's calculate the thermal engine efficiency:

η = (0.32 kJ / Q) x 100%

Next, let's calculate the refrigerator efficiency:

η_ref = (Q / 0.32 kJ) x 100%

Finally, let's calculate the temperature of the refrigerator:

T = 200°C - (η_ref x 200°C)

Please note that the specific values for Q and T cannot be determined without additional information. However, the equations provided above can be used to calculate the values once the heat input and the efficiency of the thermal engine are known.

I hope this helps! Let me know if you have any further questions.