Question

Сила тока, возникающего при освещении фотоэлемента, равна 10 мкА и в условиях этого опыта не зависит от нагрузки. Фотоэлемент присоединяют к разряженному конденсатору электроемкостью 100 мкФ. Через какое время напряжение на конденсаторе будет составлять 6 В? Ответ запишите в секундах.

Answer 1

I=q/t    t=q/I     q=C*U
t=C*U/I=100*10^-6*6/10*10^-6=60 c

Answer 2

Calculation of the Time Required for the Capacitor to Reach 6V

To calculate the time required for the capacitor to reach a voltage of 6V, we need to use the formula for the charging of a capacitor through a resistor:

V = V0 * (1 - e^(-t/RC))

Where: - V is the voltage across the capacitor at time t - V0 is the initial voltage across the capacitor (0V in this case) - t is the time in seconds - R is the resistance (in this case, the resistance is assumed to be negligible) - C is the capacitance of the capacitor (100μF in this case)

We are given that the current flowing through the photoelement is 10μA (10 * 10^-6 A) and it does not depend on the load. However, the current flowing through the photoelement is not directly related to the charging of the capacitor. Therefore, we do not need this information to calculate the time required for the capacitor to reach 6V.

Let's solve the equation for time (t) when the voltage (V) is 6V:

6 = 0 * (1 - e^(-t/(100 * 10^-6)))

Simplifying the equation, we get:

1 - e^(-t/(100 * 10^-6)) = 0

Since the exponential term is equal to 0, we can solve for t:

-t/(100 * 10^-6) = ln(1)

Taking the natural logarithm of 1 gives us 0, so:

-t/(100 * 10^-6) = 0

Simplifying further, we find:

t = 0 seconds

Therefore, the time required for the voltage across the capacitor to reach 6V is 0 seconds.

Please note that the given information does not provide enough details to accurately calculate the time required for the capacitor to charge. The equation assumes an ideal charging scenario with no resistance, which may not be the case in this experiment.