Question

Из ружья массой 3 кг производят выстрел. Пуля массой 10 г вылетает из ствола со скоростью 200 м/с. Определите скорость отдачи ружья.

Answer 1

mV=m2V1+m2V2=-m1v1+m2V2
mV=m2V2
V=0.01*200/3=0.66
И все

Answer 2

Тоже по закону импульса
mV=m2V1+m2V2=-m1v1+m2V2
начальная скорость ружья нуль
mV=m2V2
V=0.01*200/3=0.66

Answer 3

Calculation of Recoil Velocity

To determine the recoil velocity of the rifle, we can use the principle of conservation of momentum. According to this principle, the total momentum before the shot is equal to the total momentum after the shot.

The momentum of an object is calculated by multiplying its mass by its velocity. In this case, the momentum of the bullet before it is fired is given by:

Momentum of bullet before firing = mass of bullet × velocity of bullet

Given that the mass of the bullet is 10 grams (0.01 kg) and the velocity of the bullet is 200 m/s, we can calculate the momentum of the bullet before firing:

Momentum of bullet before firing = 0.01 kg × 200 m/s = 2 kg·m/s

Since the rifle is initially at rest, its momentum before the shot is zero.

According to the principle of conservation of momentum, the total momentum after the shot is equal to the total momentum before the shot. Therefore, the momentum of the rifle after the shot is also 2 kg·m/s.

The momentum of the rifle after the shot is given by:

Momentum of rifle after firing = mass of rifle × velocity of rifle

We are given that the mass of the rifle is 3 kg. Let's assume the recoil velocity of the rifle is v.

Using the principle of conservation of momentum, we can write the equation:

0 = (3 kg + 0.01 kg) × v - 2 kg·m/s

Simplifying the equation, we get:

3.01 kg × v = 2 kg·m/s

Solving for v, we find:

v = 2 kg·m/s ÷ 3.01 kg ≈ 0.6645 m/s

Therefore, the recoil velocity of the rifle is approximately 0.6645 m/s.