Question

У замкненій провідній котушці що містить 10 витків проводу, унаслідок рівномірної зміни магнітного потоку на 0.60 Вб індукувалась ЕРС індукції,що дорівнює 1.2 В. Визначте час зміни магнітного потоку й силу струму в котушці, якщо її опір 0.24 Ом

Answer 1

n=10, ΔФ= 0.6 Вб, E=1,2 В, R= 0.24 Ом.  Δt-?  I-?
E=NΔФ/Δt, Δt=nΔФ/E, Δt=10*0,6/1,2= 5 c.
I=E/R, I=1,2/0,24=5 А.

Answer 2

Calculating the Time of Change in Magnetic Flux and the Current in the Coil

To calculate the time of change in magnetic flux and the current in the coil, we can use the formula for induced electromotive force (EMF) and Ohm's law.

Given: - Number of turns in the coil (N) = 10 - Change in magnetic flux (ΔΦ) = 0.60 Wb - Induced EMF (ε) = 1.2 V - Resistance of the coil (R) = 0.24 Ω

Calculating the Time of Change in Magnetic Flux (Δt)

The induced EMF (ε) in a coil is given by the formula: \[ ε = -N \frac{ΔΦ}{Δt} \]

Solving for Δt, we get: \[ Δt = -N \frac{ΔΦ}{ε} \]

Substituting the given values: \[ Δt = -10 \frac{0.60}{1.2} \]

\[ Δt = -10 \times 0.50 \]

\[ Δt = -5 \, seconds \]

The negative sign indicates that the change in magnetic flux is decreasing, which is expected for a closed coil.

Calculating the Current in the Coil (I)

Using Ohm's law, the current (I) in the coil can be calculated using the formula: \[ I = \frac{ε}{R} \]

Substituting the given values: \[ I = \frac{1.2}{0.24} \]

\[ I = 5 \, Amperes \]

Therefore, the time of change in magnetic flux is 5 seconds and the current in the coil is 5 Amperes.