Question

СЕВА И ГРУША КУПИЛИ 8 ПИОНОВ ПО ОДИНОКОВОЙ ЦЕНЕ. СЕВА ЗАПЛАТИЛ ЗА ПИОНЫ 45 РУБ. А ГРУША-27 РУБ. СКОЛЬКО ПИОНОВ КУПИЛ КАЖДЫЙ

Answer 1

45+27=72р цена 8 пионов. 72/8=9 цена пиона 27/9=3купил груша 45/9=5 купил сева

Answer 2

1). 45+27=72 (руб) они вместе заплатили за 8 пионов; 2). 72:8=9 )руб) стоит один пион; 3). 45:9=5 (пионов) купил Сева; 4). 37:9=3 (пиона) купила Груша.

Answer 3

Solution:

To solve this problem, we can use a system of equations to represent the given information and then solve for the number of pions each person bought.

Let's denote the number of pions Seva bought as S and the number of pions Grusha bought as G. We know that Seva and Grusha together bought 8 pions, so we have the equation:

S + G = 8

We also know that Seva paid 45 rubles for the pions, and Grusha paid 27 rubles for the pions. Since the pions were bought at the same price, we can set up another equation:

45S = 27G

We can solve this system of equations to find the values of S and G.

Calculation:

Let's solve the system of equations:

S + G = 8

45S = 27G

We can solve the first equation for S:

S = 8 - G

Now, we can substitute this value of S into the second equation:

45(8 - G) = 27G

Expanding and simplifying:

360 - 45G = 27G

Bringing all the terms involving G to one side:

360 = 72G

Finally, solving for G:

G = 360 / 72 = 5

Now that we have the value of G, we can find the value of S using the equation S = 8 - G:

S = 8 - 5 = 3

Answer:

So, Seva bought 3 pions and Grusha bought 5 pions.