Question

Найти наибольший порядок спектра красного излучения с длиной волны 671 нм, если период дифракционной решетки 0.01мм

Answer 1

d sinA= K λ

K= d sinA / λ

K= 0,01*10^-3* sin90 / 671*10^-9= 14,9=14

Answer 2

Finding the Order of the Red Light Spectrum

To find the order of the red light spectrum with a wavelength of 671 nm and a diffraction grating period of 0.01 mm, we can use the formula for the order of diffraction:

Order of Diffraction (m) = (m * λ) / d

Where: - m is the order of diffraction - λ is the wavelength of light - d is the period of the diffraction grating

In this case, the wavelength of the red light is 671 nm (or 0.671 μm) and the period of the diffraction grating is 0.01 mm (or 0.01 μm).

Substituting these values into the formula, we get:

Order of Diffraction (m) = (m * 0.671 μm) / 0.01 μm

Simplifying the equation, we have:

Order of Diffraction (m) = 67.1 * m

Therefore, the order of the red light spectrum with a wavelength of 671 nm and a diffraction grating period of 0.01 mm is 67.1 times the order of diffraction.

Please note that the order of diffraction represents the number of times the light wave is diffracted by the grating. The higher the order, the more intense the diffraction pattern will be.

I hope this helps! Let me know if you have any further questions.